Hello!
61,30 grams of Sodium Iodide NaI must be used to produce 51,9 g of Iodine I₂
The reaction for the production of Iodine from NaI is the following:
2NaI(aq) + Cl₂ → I₂ + 2 NaCl
To calculate how many grams of NaI are needed to produce 51,9 g of Iodine, we use a conversion factor to go backward from grams of iodine to grams of sodium iodide. The coefficients of the reaction will help us, as well as the molar masses of each compound.
[tex]51,9gI_2* \frac{1 mol I_2}{253,809 g I_2}* \frac{2 mol NaI}{1 mol I_2} * \frac{149,89 g NaI}{1 mol NaI}=61,30 g NaI [/tex]
Have a nice day!
