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mixter17
Hello!

The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:

Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:

CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)

Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.

Have a nice day!
ajeigbeibraheem

The claim that a solution of sodium acetate in water is weakly basic is True.

What is Sodium Acetate?

Sodium acetate (CH3COONa) is a translucent deliquescent salt that can be used in a variety of ways.

  • It is used for the neutralization of sulfuric acid waste streams.
  • Serves as Pickling agent in Chrome-tanning

The reaction of Sodium acetate with water results in the hydrolysis of salt.

This is because the sodium acetate is weakly basic and therefore splits into sodium and acetate ions.

The chemical reaction of sodium acetate with water can be expressed as follows:

[tex]\mathbf{CH_3COONa \to Na^{+}_{(aq)} + CH_3COO^-_{(aq)}}[/tex]

[tex]\mathbf{CH_3COO^{-}_{(aq)} +H_2O _{(l)} \to CH_3COOH +OH^{-} _{(aq)}}[/tex]

Learn more about sodium acetate here:

https://brainly.com/question/9238250

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