Respuesta :
To determine all the different possibilities, you will find the possible choices for each position in the license and multiply them together.
1st digit - 1/5 (1,3,5,7,9)
2nd digit-1/4(4 left from above)
3rd digit-1/8 (10-2=8 possible)
4th digit-1/7 (8-1)
5th digit-1/26 (26 letters)
6th digit-1/25 (26-1)
1/5 x 1/4 x 1/8 x 1/7 x 1/26 x 1/25 =1/728000 which means there are 728000 possibilities.
1st digit - 1/5 (1,3,5,7,9)
2nd digit-1/4(4 left from above)
3rd digit-1/8 (10-2=8 possible)
4th digit-1/7 (8-1)
5th digit-1/26 (26 letters)
6th digit-1/25 (26-1)
1/5 x 1/4 x 1/8 x 1/7 x 1/26 x 1/25 =1/728000 which means there are 728000 possibilities.
There are [tex]728000[/tex] possibilities of different licence plates.
The License plate is consist of [tex]4[/tex] digits followed by [tex]2[/tex] uppercase letters, i,e,
We have [tex]6[/tex] digits so let's first check the choices of letter or digits over that.
Consider [tex]1[/tex]st Digit , according so question it should be odd so the choices we have for [tex]1[/tex]st Digits are [tex]1,3,5,7,9[/tex] i.e, [tex]5[/tex] choices we have as repitition not allowed.
Now consider [tex]2[/tex]nd Digit , according so question it should be odd so the choices we have for [tex]2[/tex]nd Digits are [tex]4[/tex] because [tex]1[/tex] odd digits has been used in [tex]1[/tex]st Digit.
[tex]3rd[/tex] digit - [tex]2[/tex] digits has been used in [tex]1[/tex]st and [tex]2[/tex]nd digits so [tex]8[/tex] choices left.
[tex]4th[/tex] digit - This is left with [tex]7[/tex] choices.
[tex]5th[/tex]- On this [tex]2[/tex] uppercase letters required so choices we have are [tex]26[/tex].
[tex]6th[/tex]- On this we have to use uppercase so [tex]25[/tex] choices are left as repitition not allowed.
So Possibility of different license [tex]5 \times 4\times\times 8\times 7\times26\times 25=728000[/tex]
Learn more about probability here;
https://brainly.com/question/11234923?referrer=searchResults
