Find the perimeter of the following shape, rounded to the nearest tenth: Shape ABCD is shown. Point A is at negative 3, 5. Point B is at 2, 6. Point C is at 0, 2. Point D is at negative 5, 1. 17.9 18 18.6 19.1

Respuesta :

 I just took this test and I found out 19.1 is the  correct answer 

Answer:

The correct option is 4. The perimeter of ABCD is 19.1.

Step-by-step explanation:

The coordinates of shape are A(-3,5), B(2,6), C(0,2), D(-5,1).

Distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

The length of all sides are

[tex]AB=\sqrt{(2-(-3))^2+(6-5)^2}=\sqrt{25+1}= \sqrt{26}[/tex]

[tex]BC=\sqrt{(0-2)^2+(2-6)^2}=\sqrt{4+16}= \sqrt{20}[/tex]

[tex]CD=\sqrt{(-5-0)^2+(1-2)^2}=\sqrt{25+1}= \sqrt{26}[/tex]

[tex]AD=\sqrt{(-5-(-3))^2+(1-5)^2}=\sqrt{4+16}= \sqrt{20}[/tex]

The perimeter of ABCD is

[tex]P=\sqrt{26}+\sqrt{20}+\sqrt{26}+\sqrt{20}[/tex]

[tex]P=2(\sqrt{26}+\sqrt{20})[/tex]

[tex]P=19.14231[/tex]

[tex]P\approx 19.1[/tex]

The perimeter of ABCD is 19.1. Therefore correct option is 4.