Using proportions, it is found that the area of a 60º sector of this circle is of [tex]7\pi[/tex] m².
Proportions:
- This question is solved by proportions, using a rule of three.
- An entire circle is of 360º, which has an area of [tex]42 \pi[/tex] m²? Which is the area equivalent to a sector of 60º?
The rule of three is:
360º - [tex]42 \pi[/tex] m²
60º - x m²
Applying cross multiplication:
[tex]360x = 60 \times 42\pi[/tex]
[tex]x = \frac{60 \times 42\pi}{360}[/tex]
[tex]x = 7\pi[/tex]
The area of a 60º sector of this circle is of [tex]7\pi[/tex] m².
To learn more about proportions, you can take a look at https://brainly.com/question/24372153
