Respuesta :
80*4=320
89*4=356
This is the range of the addition of all 4 scores.
99+80+70=249
320-249= 71
356-249= 107
[71, 100] would be the answer, unless you can get extra credit on the final.
89*4=356
This is the range of the addition of all 4 scores.
99+80+70=249
320-249= 71
356-249= 107
[71, 100] would be the answer, unless you can get extra credit on the final.
Answer: The interval would be [71,107]
Step-by-step explanation:
Since we ave given that
Scores received in 3 exams are 99%, 80%, and 70%.
To receive a grade of B in the class, he must have an average exam score between 80% and 89% for all 4 exams for all 4 exams.
So, Minimum marks he needs for all 4 exams is given by
[tex]80\times 4=320[/tex]
Maximum marks he needs for all 4 exams is given by
[tex]89\times 4=356[/tex]
And his total marks in 3 exams is
[tex]99+80+70\\\\=249[/tex]
Minimum marks he needs in final exam is given by
[tex]320-249\\\\=71[/tex]
Maximum marks he needs in final exam is given by
[tex]356-249\\\\=107[/tex]
Hence, the interval would be [71,107]