Respuesta :
Answer : The order of potential energy from least to greatest is,
(3) < (1) < (4) < (2)
Explanation :
Formula used :
[tex]P.E=m\times g\times h[/tex]
where,
P.E = potential energy
m = mass of an object
g = gravity constant = [tex]9.8m/s^2[/tex]
h = height
Now we have to calculate the potential energy of following options.
(1) Tiles a 15-kilogram stone found at a height of 3 meters.
[tex]P.E=15Kg\times 9.8m/s^2\times 3m=441J[/tex]
(2) 10 kilograms of water stored at a height of 9 meters.
[tex]P.E=10Kg\times 9.8m/s^2\times 9m=882J[/tex]
(3) 1-kilogram ball located 20 meters.
[tex]P.E=1Kg\times 9.8m/s^2\times 20m=196J[/tex]
(4) In the area box of books weighing 25 kilograms placed on a shelf 2 meters high.
[tex]P.E=25Kg\times 9.8m/s^2\times 2m=490J[/tex]
From this we conclude that, the order of potential energy from least to greatest is,
(3) < (1) < (4) < (2)
Answer:
The objects in order from least to greatest potential energy:
[tex]Ball < Stone < book < Water[/tex]
Explanation:
Potential energy is an energy of the body due to its position.
[tex]P.E=mgh[/tex]
m = mas of the body
g = Acceleration due to gravity
h = Height at which body is placed
Potential energy of the stone:
m = 15 kg, h = 3 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_1=15 kg\times 9.8 m/s^2\times 3 m=441 J[/tex]
Potential energy of the water:
m = 10 kg, h = 9 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_2=10 kg\times 9.8 m/s^2\times 9 m=882 J[/tex]
Potential energy of the ball :
m = 1 kg, h = 20 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_3=1 kg\times 9.8 m/s^2\times 20 m=196 J[/tex]
Potential energy of the book :
m = 25 kg, h = 2 m , g = [tex]9.8 m/s^2[/tex]
[tex]P.E_4=25 kg\times 9.8 m/s^2\times 2 m=490 J[/tex]
The potential energies in order from least to greatest :
[tex]P.E_3<P.E_1<P.E_4<P.E_2[/tex]
The objects in order from least to greatest potential energy:
[tex]Ball < Stone < book < Water[/tex]
