contestada

The population, in millions, of a city t years after 1990 is given by the equation P(t) = 2.9 + 0.08t. In this function, A) 0.08 million is the population of the city in 1990 and 2.9 million is the increase per year in the population. B) 2.9 million is the population of the city in 1991 and 2.98 million is the population in 1992. C) 2.9 million is the population of the city in 1990 and 0.08 million is the increase per year in the population. D) 2.9 million is the population of the city in 1990 and 0.08 million is the decrease per year in the population.

Respuesta :

The answer would be 2.9 million is the population of the city in 1990 and 0.08 million is the increase per year in the population.

Hope this helps!
calculista

Answer:

The answer is the option C

[tex]2.9[/tex] million is the population of the city in 1990 and [tex]0.08[/tex] million is the increase per year in the population

Step-by-step explanation:

Let

t------> the time in year

P(t)----->  the population in millions

we have

[tex]P(t)=2.9+0.08t[/tex]

This is a linear equation

where

The term [tex]2.9[/tex] is the y-intercept of the linear equation

The term represent [tex]2.9\ million[/tex], is the population of the city in 1990

The term [tex]0.08[/tex] is the slope of the linear equation

The term represent the increase per year in the population

[tex]0.08\frac{millions}{year}[/tex]



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