This is a right triangle, so we can use the pythagorean theorem:
[tex]\sf a^2+b^2=c^2[/tex]
Where 'a' and 'b' are the two legs of the triangle and 'c' is the hypotenuse. Plug in what we know and solve for the missing side:
[tex]\sf 24^2+b^2=26^2[/tex]
Simplify:
[tex]\sf 576+b^2=676[/tex]
Subtract 576 to both sides:
[tex]\sf b^2=100[/tex]
Take the square root of both sides:
[tex]\boxed{\sf b=10}[/tex]
So BC is equal to 10.
