Copper reacts with Nitrogen to produce Copper Nitride
6 Cu + N₂ → 2 Cu₃N
At S.T.P
22.4 L (1mole) of N₂ reacts with = 381.24 g of Cu to produce Cu₃N
So,
33.9 L of N₂ will react with = X g of Cu
Solving for X,
X = (33.9 L × 381.24 g) ÷ 22.4 L
X = 576.96 g of Cu
As,
Moles = Mass / M.mass
Moles = 576.96 g / 63.54 g/mol
Moles = 9.08 moles of Cu
Result:
So, 33.9 L of N₂ will react with 576.96 g (9.08 moles) of Cu.
