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In a titration 5.0 mL of a 2.0 M NaOH aq solution exactly neutralizes 10.0 of an HCL aq solution what is the concentration of the HCL(aq)solution

Respuesta :

kenmyna
the  concentration    of  HCl solution  is  calculated  as  follows

write  the  equation   for  reaction

NaOH  + HCl = NaCl  +  H2O

find  the  moles   NaOH  =  molarity  x volume /1000

=  5  x2/1000  =  0.01  moles

by  use  of mole  ratio  between  NaOh  to HCl  which  is 1 :1  the  the  moles of  Hcl   is  also =  0.01 moles

concentration is therefore =   moles/volume    x1000

=  0.01/10  x1000 = 1M

The concentration of HCl solution in the titration has been 1.0 M.

Titration has been defined as the neutralization reaction for the acid and base, resulting in the formation of salt and water.

The concentration in the neutralization reaction has been given by:
[tex]M_1V_1=M_2V_2[/tex]

Computation for Concentration of HCl

The given titration reaction has:

  • The volume of NaOH, [tex]V_1=5.0\;\rm mL[/tex]
  • The molarity of NaOH, [tex]M_1=2.0\;\rm M[/tex]
  • The volume of HCl, [tex]V_2=10\;\rm mL[/tex]

The concentration of HCl ([tex]M_2[/tex]) has been given as:

[tex]\rm 5.0\;mL\;\times\;2.0\;M=10\;mL\;\times\;\textit M_2\\\\ \textit M_2=\dfrac{5.0\;mL\;\times\;2.0\;M}{10\;mL}\\\\ \textit M_2=1.0\;M[/tex]

The concentration of HCl solution in the titration has been 1.0 M.

Learn more about titration, here:

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