The line width for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometers what is the probability that a line width is greater than 0.62 micrometer?
To solve the question we first calculate the z-score: z=(x-μ)/σ where: μ-mean σ-standard deviation thus from the information given we shall have: z=(0.62-0.5)/0.05 z=2.4 Thus P(x>0.62)=1-P(x<0.62) =1-P(z=2.4)=1-0.9918 =0.0082
