Respuesta :
For an electromagnetic wave, the relationship between frequency and wavelength is
[tex]c=f \lambda[/tex]
where
f is the frequency
[tex]\lambda[/tex] the wavelength
[tex]c=3 \cdot 10^8 m/s[/tex] is the speed of light.
For the wave in our problem, [tex]\lambda=7.1 \cdot 10^2 nm = 7.1 \cdot 10^{-7} m[/tex], so the frequency of the wave is
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{7.1 \cdot 10^{-7} m}=4.2 cdot 10^{14}Hz [/tex]
[tex]c=f \lambda[/tex]
where
f is the frequency
[tex]\lambda[/tex] the wavelength
[tex]c=3 \cdot 10^8 m/s[/tex] is the speed of light.
For the wave in our problem, [tex]\lambda=7.1 \cdot 10^2 nm = 7.1 \cdot 10^{-7} m[/tex], so the frequency of the wave is
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{7.1 \cdot 10^{-7} m}=4.2 cdot 10^{14}Hz [/tex]
The frequency of light for which the wavelength is [tex]7.1 \times {10^2}\,{\text{nm}}[/tex] is [tex]\boxed{0.423 \times {10^{15}}\,{\text{Hz}}}[/tex] or [tex]\boxed{4.23 \times {10^{14}}\,{\text{Hz}}}[/tex].
Further explanation:
The frequency is a measure of number of wave’s that passes through a fixed point or place in a given time interval. The unit of frequency is [tex]\text{cycle/sec}[/tex] or [tex]\text{Hz}[/tex]. Hertz [tex](\text{Hz})[/tex] is the S.I unit of frequency.
Wavelength is defined as the distance between two successive crests or troughs of a travelling wave.
Examples of waves are sound wave, light wave, mechanical waves, surface waves etc.
Given:
The wavelength of the light used is [tex]7.1\times {10^2}\,{\text{nm}}[/tex].
The speed of the light is [tex]3.00\times10^{8}\text{ m/s}[/tex].
Concept:
Light is an electromagnetic wave which carry energy in the form of electric field and magnetic field. The speed of light in vacuum is [tex]3.00 \times {10^8}\,{\text{m/s}}[/tex].
The speed of light can be expressed in terms of wavelength of the light and the frequency of the light.
The speed of light is:
[tex]c=f \cdot \lambda[/tex]
Rearrange the above expression.
[tex]\boxed{f=\dfrac{c}{\lambda }}[/tex] …… (1)
Here, [tex]f[/tex] is the frequency of the light, [tex]c[/tex] is the speed of the light in vacuum and [tex]\lambda[/tex] is the wavelength of the light.
Substitute [tex]3.00 \times {10^8}\,{\text{m/s}}[/tex] for [tex]c[/tex] and [tex]7.1 \times {10^2}\,{\text{nm}}[/tex] for [tex]\lambda[/tex] in equation (1) .
[tex]\begin{aligned}f&=\frac{{3.00 \times {{10}^8}\,{\text{m/s}}}}{{\left( {7.1 \times {{10}^2}\,{\text{nm}}} \right)\left( {\frac{{1 \times {{10}^{ - 9}}\,{\text{m}}}}{{1\,{\text{nm}}}}} \right)}} \\&=0.423 \times {10^{15}}\,{\text{Hz}} \\ \end{aligned}[/tex]
Thus, the frequency of light for which the wavelength is [tex]7.1 \times {10^2}\,{\text{nm}}[/tex] is [tex]\boxed{0.423 \times {10^{15}}\,{\text{Hz}}}[/tex] or [tex]\boxed{4.23 \times {10^{14}}\,{\text{Hz}}}[/tex].
Learn more:
1. Conservation of energy brainly.com/question/3943029
2. Charge on a capacitor https://brainly.com/question/8892837
3. Energy levels https://brainly.com/question/6054540
Answer Details:
Grade: College
Subject: Physics
Chapter: Electromagnetic wave
Keywords:
Frequency, light, wavelength, 7.1times10^2 nm, 7.1times10^-7 m, 0.423times10^15 hz, 4.23imes10^14 hz, vacuum, air, crests, troughs, sound wave, light wave, mechanical wave.
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