Respuesta :
[tex] \frac{-b+- \sqrt{b^{2} -4ac } }{2a} [/tex]
This is the solution of the equation, where a=1, b=-5, c=7
So the discriminant is :
b^2-4ac=25-4*7= -3
The square root of -3 is non-real, this both solutions are non-real.
This is the solution of the equation, where a=1, b=-5, c=7
So the discriminant is :
b^2-4ac=25-4*7= -3
The square root of -3 is non-real, this both solutions are non-real.
Answer:
D) non-real roots
Step-by-step explanation:
In the quadratic equation [tex]ax^2 + bx + c = 0, a \neq 0[/tex] and
we know that the discriminant d = [tex]b^2 - 4ac[/tex].
if d <0, then the roots are non-real roots
if d = 0, then double roots.
if d >0, then the roots are real and rational/irrational.
We are given [tex]x^2 -5x + 7 = 0[/tex]
Here a = 1, b = -5 and c = 7.
Let's find the discriminant d = [tex](-5)^2 - 4*1*7[/tex]
d = 25 - 28
d = -3
Which is less than zero.
d < 0, so the roots are non-real according the definition stated above.
The answer is D) non-real roots