Hello!
This question can be easily solved using the Mole Ratio of KNO₃/KI in the balanced reaction that is shown below:
2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂
The Mole Ratio of KNO₃/KI in this reaction is 2 moles KNO₃/ 2 moles KI so we can apply the following conversion factor:
[tex]0,03 moles KI * \frac{2 moles KNO_3}{2 moles KI}=0,03 moles KNO_3 [/tex]
So, if 0,03 moles of KI are completely consumed, 0,03 moles of KNO₃ are formed.
Have a nice day!
