lolil1
contestada

Lucy and her bike together have a mass of 120kg. She slows down from 4.5m/s to 3.5m/s. How much kinetic energy does she lose?

Respuesta :

skyluke89
The kinetic energy of a moving object is given by
[tex]K= \frac{1}{2}mv^2 [/tex]
where m is the object's mass and v its velocity.

In our problem, the initial kinetic energy is:
[tex]K_i = \frac{1}{2} m v_i^2 = \frac{1}{2}(120 kg) (4.5 m/s)^2=1215 J[/tex]

while the final kinetic energy is:
[tex]K_f = \frac{1}{2}mv_f^2 = \frac{1}{2}(120 kg)(3.5 m/s)^2= 735 J [/tex]

So, the kinetic energy lost by Lucy and her bike is
[tex]\Delta K = K_i - K_f = 1215 J - 735 J = 480 J[/tex]
okpalawalter8

We have that the kinetic energy lost  is mathematically given as

KL=480J

Kinetic energy

Generally the equation for the Kinetic energy  is mathematically given as

K=0.5mv^2

Therefore

K=0.5(120(4.5)v^2

K=1215J

And

K=0.5(120(3.5)v^2

K=725J

Henec enegy lost

KL=1215J-725J

KL=480J

For more information on Kinetic energy visit

https://brainly.com/question/999862

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