Let f(x)=100−10+e−0.1x .

What is f(−2) ?


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Let's solve for x.

f(x)= 100−10+e−0.1x

Step 1: Add 0.1x to both sides.

xf+0.1x=−0.1x+e+90+0.1x

xf+0.1x = e+90

Step 2: Factor out variable x.

x(f+0.1) = e+90

Step 3: Divide both sides by f+0.1.

x(f+0.1)/ f+0.1 =e+90/ f+0.1

x=e+90/ f+0.1

Answer:

x= e+90/ f+0.1

Answer:

f(-2) = 87.8

Step-by-step explanation:

Given :  function [tex]f(x)=100-10e^{(-0.1x)}[/tex]

We have to find f(-2)

Consider the given function [tex]f(x)=100-10e^{(-0.1x)}[/tex]

We have to find f (-2) that is value of function f(x) at x = -2

Put x = -2 in function given , we have,

[tex]f(-2)=100-10e^{-0.1\left(-2\right)}[/tex]

[tex]\mathrm{Apply\:rule}\:-\left(-a\right)=a[/tex]

[tex]=100-10e^{0.1\cdot \:2}[/tex]

Multiply , we have,

[tex]=100-10e^{0.2}[/tex]

We know [tex]e^{0.2}=1.22140\dots[/tex]

So, [tex]10e^{0.2}=12.21403\dots[/tex]

Subsitute and solve, we have,

[tex]f(-2)=100-12.21403\dots=87.78597\dots[/tex]

Thus, f(-2) = 87.8