Respuesta :

mixter17
Hello!

First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL

Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:

[tex][CH_3CO_2H]=\frac{8 g_{CH_3CO_2H} }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }[/tex]

[tex][CH_3CO_2H]=0,1818 M[/tex]

So, the concentration of acetic acid would be 0,1818 M

Have a nice day!
mahima6824soni

The molarity of the solution is  0.1818 m.

What is molality?

Molality is the measure of the moles of any solute in a solution per unit kg of the solvent.

The density of water is 1 g/ml

The volume will be 725 ml

The density of acetic acid is 1.05 g/ml

Calculating the molarity

[tex]\rm CH_3CO_2H = \dfrac{8\;g}{725g \times 7.61g} \times \dfrac{1000ml}{1\;L} \times \dfrac{1\;mol}{60.05\;g} = 0.1818 \;M[/tex]

Thus, the molarity of acetic acid is 0.1818 m

Learn more about molarity, here:

https://brainly.com/question/12127540

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