What is the average rate of change for this quadratic function for the interval from x=1 to x=3?
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Answer:
The average rate of change is [tex]-4[/tex]
Step-by-step explanation:
we know that
the average rate of change using the graph is equal to
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
In this problem we have
[tex]f(a)=f(1)=0[/tex]
[tex]f(b)=f(3)=-8[/tex]
[tex]a=1[/tex]
[tex]b=3[/tex]
Substitute
[tex]\frac{-8-0}{3-1}=-4[/tex]
Answer:
The average rate of change of function is -4 in [1,3]
Step-by-step explanation:
The average rate of change for graphic quadratic function for the interval from x=1 to x=3
The average rate of change of a function is change y over change in x.
[tex]\text{Average rate of change of function}=\dfrac{f(b)-f(a)}{b-a}[/tex]
where,
a=1 and b=3
Using graph we will find f(1) and f(3)
f(3)=-8
f(1)=0
[tex]\text{Average rate of change of function}=\dfrac{f(3)-f(1)}{3-1}[/tex]
[tex]\text{Average rate of change of function}=\dfrac{-8-0}{2}=-4[/tex]
Hence, The average rate of change of function is -4 in [1,3]