Respuesta :
the chemical equation
2AgNO3 (aq) + K2SO4 (aq) = Ag2SO4 (s) + 2KNO3(aq)
ionic equation
2Ag^+(aq) + 2 NO3^-(aq) + 2k^+(aq) + SO4^ 2-(aq) = Ag2SO4(s) +2K ^+(aq) + 2NO3 ^-(aq)
the spectator ion is therefore = 2k^+ and 2NO3^-
therefore net ionic equation = 2Ag^+(aq) + SO4^2- = Ag2So4(s)
2AgNO3 (aq) + K2SO4 (aq) = Ag2SO4 (s) + 2KNO3(aq)
ionic equation
2Ag^+(aq) + 2 NO3^-(aq) + 2k^+(aq) + SO4^ 2-(aq) = Ag2SO4(s) +2K ^+(aq) + 2NO3 ^-(aq)
the spectator ion is therefore = 2k^+ and 2NO3^-
therefore net ionic equation = 2Ag^+(aq) + SO4^2- = Ag2So4(s)
Answer: The spectator ions in the solution will be [tex]K^+\text{ and }NO_3^-[/tex]
Explanation: Spectator ions are the ions which are present in the same form on both the sides of a chemical reaction.
For a given Chemical reaction:
[tex]2AgNO_3(aq.)+K_2SO_4(aq.)\rightarrow Ag_2SO_4(s)+2KNO_3(aq.)[/tex]
precipitate formed is silver sulfate.
The Ionic equation for the above chemical reaction is:
[tex]2Ag^+(aq.)+2NO_3^-(aq.)+2K^+(aq.)+SO_4^{2-}(aq.)\rightarrow Ag_2SO_4(s)+2K^+(aq.)+2NO_3^-(aq.)[/tex]
As, [tex]K^+\text{ and }NO_3^-[/tex] do not precipitate and hence, are considered as the spectator ions.
Net Ionic equation becomes:
[tex]2Ag^+(aq.)+SO_4^{2-}(aq.)\rightarrow Ag_2SO_4(s)[/tex]