What are the spectator ions in the solution after the precipitation of an insoluble sulfate compound from AgNO3(aq) and K2SO4(aq)?

Respuesta :

the     chemical  equation
2AgNO3  (aq)  +  K2SO4 (aq) = Ag2SO4 (s)   +  2KNO3(aq)

ionic  equation
 2Ag^+(aq)  +  2 NO3^-(aq)  +  2k^+(aq)  +  SO4^ 2-(aq)  =   Ag2SO4(s)  +2K ^+(aq) +    2NO3  ^-(aq)

the  spectator   ion  is  therefore =  2k^+   and  2NO3^-

therefore  net  ionic  equation  =    2Ag^+(aq)   + SO4^2-  =  Ag2So4(s)

Answer: The spectator ions in the solution will be [tex]K^+\text{ and }NO_3^-[/tex]

Explanation: Spectator ions are the ions which are present in the same form on both the sides of a chemical reaction.

For a given Chemical reaction:

[tex]2AgNO_3(aq.)+K_2SO_4(aq.)\rightarrow Ag_2SO_4(s)+2KNO_3(aq.)[/tex]

precipitate formed is silver sulfate.

The Ionic equation for the above chemical reaction is:

[tex]2Ag^+(aq.)+2NO_3^-(aq.)+2K^+(aq.)+SO_4^{2-}(aq.)\rightarrow Ag_2SO_4(s)+2K^+(aq.)+2NO_3^-(aq.)[/tex]

As, [tex]K^+\text{ and }NO_3^-[/tex] do not precipitate and hence, are considered as the spectator ions.

Net Ionic equation becomes:

[tex]2Ag^+(aq.)+SO_4^{2-}(aq.)\rightarrow Ag_2SO_4(s)[/tex]