Hello!
To solve this problem we will use the dilution reaction, assuming that the number of moles of Salicylic Acid (SA) taken from the first solution will be the same as the total moles in the second solution and clear for the concentration of salicylic acid in the second solution:
[tex]molesSA_1=molesSA_2 \\ \\ cSA_1*VSA_1=cSA_2*VSA_2 \\ \\ cSA_2= \frac{cSA_1*VSA_1}{VSA_2} = \frac{200 mL * 9M}{1000 mL}=1,8 M [/tex]
So, the concentration of Salicylic Acid in the second solution would be 1,8M
Have a nice day!
