A photon has 3.4 × 10–18 joules of energy. Planck’s constant is 6.63 × 10–34 J•s. What is the frequency of the photon? 5.12 × 10–15 Hz 1.95 × 1016 Hz 5.12 × 1015 Hz 1.95 × 10–16 Hz

Respuesta :

For this problem, you can use the equation that represents the relationship between energy, frequency, and Planck’s constant. This formula is:

E=hu

where E is energy, u is frequency, and h is planck’s constant. Plugging in your numbers and solving for u:

(3.4x10^-18)=(6.626x10^-34)(u)
u=5.13x10^15 hertz, or the third option.

Taking into account the definition of photon and energy of a photon, the frequency of the photon is 5.13×10¹⁵ Hz.

Definition of photon and energy of a photon

You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:

E=h×f

Frequency of he photon

In this case, you know:

  • E= 3.4×10⁻¹⁸ J
  • h=  6.63*10⁻³⁴ Js
  • f= ?

Replacing:

3.4×10⁻¹⁸ J= 6.63×10⁻³⁴ Js ×f

Solving:

3.4×10⁻¹⁸ J÷ 6.63×10⁻³⁴ Js= f

5.13×10¹⁵ Hz= f

Finally, the frequency of the photon is 5.13×10¹⁵ Hz.

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