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Determine ƒ(–a) where ƒ(x) = x2– 6x and simplify.


ƒ(–a) = a2 – 6a

ƒ(–a) = –a2 + 6a

ƒ(–a) = a2 + 6a

ƒ(–a) = –a2 – 6a

Respuesta :

altavistard
Please use "^" to denote exponentiation:  f(x) = x^2 - 6x.

To find f(-a), replace "x" with "(-a)" in the function (x) = x^2 - 6x:

f(-a) = (-a)^2 - 6(-a)  =  a^2 + 6a (answer)

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