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P is a rectangle with a length 40 cm and width x cm
Q is a rectangle with width y cm
the length of Q is 25% more than the length of p
the area of Q is 10% less than the area of p
work out the ratio of x:y
give your answer in its simplest form

P is a rectangle with a length 40 cm and width x cm Q is a rectangle with width y cm the length of Q is 25 more than the length of p the area of Q is 10 less th class=

Respuesta :

calculista
we know that

the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18

the answer 
the ratio x:y is 25:18

x : y  is 25 : 18

Rectangle P

  • length = 40 cm
  • width = x

Rectangle Q

  • width = y cm

The length of Q is 25% more than the length of P. Therefore,

  • length of Q = (25% of 40) + 40 = 10 + 40 = 50 cm

The area of Q is 10% less than the area of P

  • area of Q = 40x - (10% of 40x)

Area of Q = 50y

50y = 40x - 4x

50y = 36x

divide both sides by 2

25y = 18x

25 = 18x/y

25/18  = x/y

x : y  is 25 : 18

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