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How many liters of methane gas (CH4) need to be combusted to produce 8.5 liters of water vapor, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem. CH4 (g) + 2O2 (g) CO2 (g) + 2H2O (g)

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1 mole of CH4 results to 2 moles of H2O.

If 8.5 liters are to be produced, then (1CH4/2H20)*(8.5L h2o) = 4.25L CH4

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