contestada

In the reaction N2 + 3H2 ⇌ 2NH3, an experiment finds equilibrium concentrations of [N2] = 0.1 M, [H2] = 0.05 M, and [NH3] = 0.001 M. What is the equilibrium constant Kc for this reaction?
a. 0.08
b. 0.20
c. 5.0
d. 12.5

Respuesta :

kenmyna
  The   equilibrium  constant  Kc   for  this  reaction    is  calculated  as  follows

from  the  equation   N2  + 3H2 =2 NH3

   qc =   (NH3)2/{(N2)(H2)^3}


Qc   is  therefore  = ( 0.001)2  /{(0.1) (0.05)^3}  = 0.08

Answer: [tex]K_c[/tex] = 0.08

Explanation: The given balanced equation is:

[tex]N2+3H_2\rightleftharpoons 2NH_3[/tex]

equilibrium expression is written as:

[tex]K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}[/tex]

Equilibrium concentrations are given for products and reactants. Let's plug in the values.

[tex]K_c=\frac{(0.001)^2}{(0.1)(0.05)^3}[/tex]

[tex]K_c[/tex] = 0.08

So, the correct choice is A) 0.08.

Otras preguntas