Respuesta :
We can solve the problem by using De Broglie's relationship:
[tex]p= mv= \frac{h}{\lambda} [/tex]
where
p is the momentum of the particle
m is the the mass
v is the velocity
h is the Planck constant
[tex]\lambda[/tex] is the wavelength of the particle
By re-arranging the equation, we get
[tex]\lambda = \frac{h}{mv} [/tex]
and by using the data about the proton mass and speed, we find its wavelength:
[tex]\lambda= \frac{6.6 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.0 \cdot 10^6 m/s)}=7.95 \cdot 10^{-14} m [/tex]
[tex]p= mv= \frac{h}{\lambda} [/tex]
where
p is the momentum of the particle
m is the the mass
v is the velocity
h is the Planck constant
[tex]\lambda[/tex] is the wavelength of the particle
By re-arranging the equation, we get
[tex]\lambda = \frac{h}{mv} [/tex]
and by using the data about the proton mass and speed, we find its wavelength:
[tex]\lambda= \frac{6.6 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.0 \cdot 10^6 m/s)}=7.95 \cdot 10^{-14} m [/tex]
The wavelength is indirectly proportional to the mass and velocity of the particle. The wavelength of the given proton is [tex]7.95 \times 10^{-14}[/tex].
From de Broglie's relationship:
[tex]\lambda = \dfrac h{mv}[/tex]
Where,
[tex]m[/tex] - mass = [tex] 1.66 \times 10^{-27}\rm \ kg [/tex]
[tex]v[/tex] - velocity = [tex]5.0 \times 10^6 \rm \ m/s[/tex]
[tex]h[/tex] - Planck constant = [tex] {6.6\times 10^{-34}}\rm \ Js[/tex]
[tex]\lambda [/tex] - wavelength of the particle = ?
Put the values in the formula,
[tex]\lambda = \dfrac {6.6\times 10^{-34}}{(1.66\times 10^{-27})(5.0 \times 10^6)}\\\\ \lambda = 7.95 \times 10^{-14}[/tex]
Therefore, the wavelength of the given proton is [tex]7.95 \times 10^{-14}[/tex].
Learn more about De Broglie's relationship:
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