For this case we can use the following trigonometric relationship to solve the problem:
[tex]sin(x)= \frac{C.O}{h} [/tex]
Where,
C.O: opposite leg
h: hypotenuse
Substituting values we have:
[tex]sin(x)= \frac{32}{58} [/tex]
Clearing x we have:
[tex]x = arcsin(\frac{32}{58})[/tex]
Making the corresponding calculations we have:
[tex]x = 33.49[/tex]
Answer:
The value of x is given by:
[tex]x = 33.49[/tex]
