well, let's recall that the diameter is twice as long as the radius, let's find the radius firstly then,
[tex]\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
-----\\
A=94\pi
\end{cases}\implies 94\pi =\pi r^2\implies \cfrac{94\pi }{\pi }=r^2
\\\\\\
94=r^2\implies \sqrt{94}=r\\\\
-------------------------------\\\\
\textit{so the diameter is twice as much}\qquad 2\sqrt{94}[/tex]
sadly, the one above is only for a circle with 94π as area, not for 94 pie, but yours sounds more delicious.
