The small piston in a hydraulic system has a cross-sectional area of 0.5 m2, and the large piston has an area of 3m3. What is the force exerted by the large piston if a force of 500 N is exerted on the small piston?

Respuesta :

     Considering the fluid as ideal, the pressure will spread throughout its volume. Thus,

[tex] \frac{F_1}{A_1}= \frac{F_2}{A_2} \\ F_2= \frac{3\times 500}{0.5} \\ \boxed {F_2=3000N}[/tex]

If you notice any mistake in my english, please let me know, because my english level is still low.