Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers):

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10-05-2018
Chemistry

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Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers):

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transitionstate transitionstate · Answer 1 · 2018-05-20T23:40:20+02:00

The two possible enantiomers for the starting material and the products are shown below,

Where;
J =  (S)-1,4-dimethylcyclobut-1-ene
Or,
J =  (R)-1,4-dimethylcyclobut-1-ene
And,
K =  1,2-dimethylcyclobutane

Both enantiomers have same molecular formula (C₆H₁₀) but different stereochemistry about chiral carbon.

Upon catalytic hydrogenation two hydrogen atoms are added across double bond resulting in the formation of cyclobutane.