To find the molecular mass, we divide the molar mass by the molar mass of [tex]CO_3[/tex], round to a whole number and multiply the solution by the empirical formula.
Molar Mass of [tex]CO_3[/tex] = [tex]60.01g/mol[/tex]
[tex]\frac {120.0g/mol}{60.01g/mol} = 1.999 =2[/tex]
[tex]2*CO_3 = C_3O_6[/tex]
The answer is [tex]C_3O_6[/tex]
