Answer:
[tex]x=-\sqrt{11}\text{ or }x=\sqrt{11}[/tex]
Step-by-step explanation:
We have been given an equation [tex]0.2x^2+1.2=3.4[/tex]. We are asked to solve the given equation.
[tex]0.2x^2+1.2-1.2=3.4-1.2[/tex]
[tex]0.2x^2=2.2[/tex]
[tex]\frac{0.2x^2}{0.2}=\frac{2.2}{0.2}[/tex]
[tex]x^2=11[/tex]
Take square root of both sides:
[tex]x=\pm\sqrt{11}[/tex]
[tex]x=-\sqrt{11}\text{ or }x=\sqrt{11}[/tex]
Therefore, the solutions for our given equation would be [tex]x=-\sqrt{11}\text{ or }x=\sqrt{11}[/tex].
