Areas of paralleolgrams and triangles?
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The area of parallelogram is
[tex] A=base\cdot height [/tex].
If base has length 9.9 in and height has length 5.5 in, then the area is [tex] A=9.9\cdot 5.5=54.45 [/tex] sq. in.
When base has length 11 in and height is unknown h, then [tex] A=11\cdot h [/tex].
Since the area is 54.45 sq. in., then
[tex] 54.45=11h,\\ \\ h=\dfrac{54.45}{11} =4.95 [/tex] in.
Answer: h=4.95 in.