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James walked around two rectangular Parks one measures 5423 CM by 3978 cm and the other measures 2903 CM by 1846 cm how far did he walk

James brother walk around at different park that is 8012 CM by 3456 CM what is the difference in the distance each one walked

Respuesta :

calculista

Answer:

Part a) James walked [tex]31,520\ cm[/tex]

Part b) The difference in distance each one walked is [tex]8,584\ cm[/tex]

Step-by-step explanation:

we know that

The perimeter of a rectangle is equal to

[tex]P=2(L+W)[/tex]

step 1

Find the perimeter Park 1

[tex]P=2(5,423+3,978)=18,802\ cm[/tex]

Find the perimeter Park 2

[tex]P=2(2,903+3,456)=12,718\ cm[/tex]

To calculate how far James walked, sum the perimeter park 1 and the perimeter Park 2

so

[tex]18,802\ cm+12,718\ cm=31,520\ cm[/tex]

step 2

James brother

Find the perimeter of the different park

[tex]P=2(8,012+3,456)=22,936\ cm[/tex]

step 3

Find the difference in distance each one walked

[tex]31,520\ cm-22,936\ cm=8,584\ cm[/tex]

kennyoverstreet55

Answer:

part a is 7075

Step-by-step explanation:

Add all together

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