we are given
[tex]x^2 +3x -10[/tex]
it's factor as (x+p)(x+q)
so, we can write as
[tex]x^2 +3x -10= (x+p)(x+q) [/tex]
we can simplify it
[tex]x^2 +3x -10= x^2 +(p+q)x +pq [/tex]
now, we can compare both sides
coefficient of x must be equal
so, we get
[tex]3= (p+q) [/tex]
[tex](p+q)=3 [/tex]
now, we can look at the table where p+q =3
so, we can see that when p+q=3 .... then p=-2 and q=5
so, option-A.......Answer
