Given the concentration of glucose solution = 0.50 M
That means 1 L solution has 0.50 mol glucose dissolved.
The given volume of the solution = 500 mL
Converting the volume from mL to L:
[tex]500 mL*\frac{1 L}{1000 mL}=0.500L[/tex]
Calculating the moles of glucose in 0.500 L solution:
[tex]0.500L*\frac{0.50mol}{L} =0.25mol[/tex]
Converting the moles of glucose to mass using the molar mass of glucose (180g/mol):
[tex]0.250mol *\frac{180g}{1 mol}=45g[/tex]
Therefore, 45 g glucose is to be dissolved in 500 mL to prepare a 0.5 M solution.
