Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence of modifyingbelow lim with x right arrow c f left parenthesis x right parenthesislimx→c f(x)​? give reasons for your answer.

Respuesta :

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

[tex] \lim_{x \to c} \frac{x^2-cx}{(x-c)}[/tex]

We can simplify it

[tex] \lim_{x \to c} \frac{x(x-c)}{(x-c)}[/tex]

[tex] =\lim_{x \to c} x[/tex]

[tex] =c[/tex]

so, we can see that limit exist and it's value defined

case-2:

[tex] \lim_{x \to c} \frac{1}{(x-c)}[/tex]

Left limit is

[tex] \lim_{x \to c-} \frac{1}{(x-c)}[/tex]

[tex] =-\infty[/tex]

Right Limit is

[tex] \lim_{x \to c+} \frac{1}{(x-c)}[/tex]

[tex] =+\infty[/tex]

so, we can see that left limit is not equal to right limit

so, limit does not exist