we can use formula
[tex]P(t)=P_0e^{-kt}[/tex]
we are given
[tex]P_0=1[/tex]
strontium-90, which decays exponentially at a rate of approximately 2.5 % per year
so,
[tex]k=0.025[/tex]
now, we can plug these values
and we get
[tex]P(t)=1e^{-0.025t}[/tex]..........Answer