We have that Clarence sells yearly subscriptions to a particular magazine.
He sells at least 10 and not more than 25 subscriptions each week.
The function f(t) = 48t represents the amount of money earned for selling t subscriptions each week.
So;
10 ≤ t ≤ 25
f(t) therefore is 48(10) ≤ f(t) ≤ 48(25)
This gives: 480 ≤ f(t) ≤ 1200
So the amount of money earned f(t) for selling t subscriptions each week is all multiples of 48 between 480 and 1200, inclusive.
Answer:
A.All multiples of 48 between 480 and 1200 inclusive
Step-by-step explanation:
We are given that
Clarence sells yearly subscriptions to a particular magazine.
The function
[tex]f(t)=48t[/tex]
Where f(t) represents the amount of money earned for selling t subscriptions each week.
[tex]10\leq t\leq 25[/tex]
We have to find the practical range of the function.
Substitute t=10 then we get
[tex]f(10)=48(10)=480[/tex]
Substitute t=25
[tex]f(25)=48(25)=1200[/tex]
The range of function
[tex]480\leq f(t)\leq 1200[/tex]
All multiples of 48 between 480 and 1200 inclusive
Hence,option A is true.
