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Kaylib’s eye-level height is 48 ft above sea level, and Addison’s eye-level height is 85 1/3 ft above sea level. How much farther can Addison see to the horizon? Use the formula d=sqrt 3h/2, with d being the distance they can see in miles and h being their eye-level height in feet.

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SonOfZeus

Answer:

Addison can see 2.82 miles farther.

Step-by-step explanation:

Via the equation given [tex]d=\sqrt{\frac{3h}{2}}[/tex]

Let's calculate Kaylib's and Addison's distance they can see in miles and then calculate the difference therefore:


[tex]d_{Kaylib}=\sqrt{\frac{3 \times 48}{2}} = 8.49mi[/tex]

[tex]d_{Addison}=\sqrt{\frac{(3)(85+1/3)}{2}} = 11.31mi[/tex]

And the difference is:

11.31  - 8.49 = 2.82 mi.

Answer:

B!!!!!!

2√ 2 mi

Step-by-step explanation:

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