The cell notation is:
[tex]Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)[/tex]
here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell
in anodic half cell : oxidation takes place [loss of electrons]
in cathodic half cell: reduction takes place [gain of electrons]
1) this is a galvanic cell
2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode
[tex]E^{0}_{Mg}=-2.38V[/tex]
[tex]E^{0}_{Ag}=+0.80V[/tex]
Therefore
[tex]E^{0}_{cell}=0.80-(-2.38)=+3.18V[/tex]
3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative
Δ[tex]G^{0}=-nFE^{0}[/tex]
As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.
