LaneseM
contestada

a 10 foot ladder rests against a brick wall at an angle of 65 degrees. What is the value of x to the nearest tenth of a foot?

a 10 foot ladder rests against a brick wall at an angle of 65 degrees What is the value of x to the nearest tenth of a foot class=

Respuesta :

Answer:

Option C. The value of x is [tex]4.2\ ft[/tex]

Step-by-step explanation:

we know that

In the right triangle of the figure

[tex]cos(65\°)=\frac{x}{10} \\ \\ x=10cos(65\°)\\ \\x= 4.2\ ft[/tex]

Answer:

C ) x = 4.2 feet .

Step-by-step explanation:

Given  : A  10 foot ladder rests against a brick wall at an angle of 65 degrees.

To find : What is the value of x to the nearest tenth of a foot.

Solution : We have given a triangle with angle 65 degree and

hypotenuse = 10 feet .

By the trigonometric ration

Cos(Ф) = [tex]\frac{adjecent}{hypotenuse}[/tex]

Plugging the values

Cos(65) =  [tex]\frac{x}{10}[/tex].

0.422 =   [tex]\frac{x}{10}[/tex].

On multiplying by 10 both sides

0.422 * 10 =  x

4.22 = x

x = 4.22

x = 4.2 feet ( nearest tenth ).

Therefore, C ) x = 4.2 feet .