Answer:
[tex]5.4 \Omega[/tex]
Explanation:
The reactance in case of a capacitive circuit is given by:
[tex]X_C = \frac{1}{2 \pi f C}[/tex]
where
f is the frequency
C is the capacitance
In this problem, we have
[tex]f=8.0 Hz[/tex]
[tex]C=3.7 mF=0.0037 F[/tex]
Substituting into the equation above, we find the reactance:
[tex]X_C = \frac{1}{2\pi (8.0 Hz)(0.0037 F)}=5.4 \Omega[/tex]
