Respuesta :

Answer:

[tex][B]=2[/tex]

Step-by-step explanation:

[tex]B=\left[\begin{array}{ccc}3x-5&-3+2y\\11-3x&2y-5\end{array}\right][/tex]

With [tex]x=3[/tex] and [tex]y=4[/tex]

[tex]B=\left[\begin{array}{ccc}3(3)-5&-3+2(4)\\11-3(3)&2(4)-5\end{array}\right][/tex]

[tex]B=\left[\begin{array}{ccc}9-5&-3+8\\11-9&8-5\end{array}\right][/tex]

[tex]B=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right][/tex]

solving the determinant of matrix B

[tex][B]=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right]=(4.3-5.2)=(12-10)=2[/tex]

I think the answer is (B)=2(B)=2 Im not 100% sure though.