contestada

Consider the following intermediate chemical equations.
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
2H2O(g) → 2H2O(1)
Which overall chemical equation is obtained by combining these intermediate equations?
CH4(g)+2O2(g) → CO2(g) + 2H2O(1)
CH4(g) +202(g) → CO2(g) + 2H2O(g)
CH4(g) + 2O2(g) → CO2(g) + 4H2O(g) + 2H2O(1)
CH4(g) + 2O2(g) → CO2(g) + 6H2O(g)

Respuesta :

superman1987

Answer:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).

Explanation:

  • We have two equations:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

2H₂O(g) → 2H₂O(l)

  • To add the two equations: we omit H₂O(g)  that is formed by 2 moles in the product side of the first equation and consumed by 2 moles from the reactants side in the second equation

  • So, the overall chemical equation is obtained by combining these intermediate equations is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).

Answer:  The reaction is Exothermic

CH4(g) + 2O2(g) > CO2(g) + 2H2O(g) + energy

Explanation:

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