Answer:
y=2x-3
Step-by-step explanation:
The slope-intercept form of a linear equation is y=mx+b where m is the slope and b is the y-intercept.
The y-intercept is where it crosses the y-axis. It cross the y-axis in your picture at -3 so b=-3.
Now the slope=rise/run. So starting at (0,-3) we need to find another point that crosses nicely on the cross-hairs and count the rise to and then the run to it. So I see (1,-1) laying nicely. So the rise is 2 and the run is 1.
If you don't like counting. You could just use the slope formula since we already identified the two points as (-1,1) and (0,-3).
The way I like to use the formula is line up the points and subtract vertically then put 2nd difference over 1st difference.
(0,-3)
-(1,-1)
----------
-1 -2
So the slope is -2/-1 or just 2.
We have that m is 2 and b is -3.
Plug them into y=mx+b and you are done.
y=2x-3.
Slope intercept equation of the line is y = 2x - 3.
Slope intercept form gives the graph of a straight line and is represented in the form of y=mx + c.
By checking the graph by drawing manually.
From that we get the equation
y = 2x - 3
Comparing above equation with the standard slope-intercept form y = mx +c, we get
Slope : m = 2
Now, given equation can be re-written as :
2x - y = 3
Divide by 3 on both sides
[tex]\frac{2x}{3} -\frac{y}{3} =\frac{3}{3}[/tex]
[tex]\frac{x}{\frac{3}{2} } -\frac{y}{3} =1[/tex]
Comparing above equation with intercept form:
[tex]\frac{x}{a}+\frac{y}{b}=1[/tex], we get
x-intercept : [tex]a=\frac{3}{2}[/tex]
y-intercept : [tex]b=-3[/tex]
Now the given straight line intersects the coordinate axes at [tex](\frac{3}{2} ,0)[/tex] and [tex](0,-3)[/tex]. Specify these plots on XY-plane & join by a straight line to get a plot.
Find out more information about slope-intercept form here
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