Calculate these masses.
(a) What is the mass of 6.00 cm3 of mercury, density= 13.5939 g/cm3?
(b) What is the mass of 25.0 mL octane, density= 0.702 g/cm3?

Respuesta :

A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g

B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g

1mL = 1cm3

Answer:

(a) [tex]m = 81.6g[/tex]

(b) [tex]m = 17.6g[/tex]

Explanation:

Hello,

In this case, we consider the formula of density and solve for the required mass in each statement:

[tex]\rho =\frac{m}{V} \\m=\rho *V[/tex]

In such a way we compute them as:

(a) [tex]m=6.00cm^3*13.5939g/cm^3=81.6g[/tex]

(b) [tex]m=25.0 mL*\frac{1cm^3}{1mL}*0.702g/cm^3 =17.6g[/tex]

Best regards.