You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point B to another point C, moving at a constant speed of 90 km/h. Is your average speed for the entire trip from A to C equal to 80 km/h? Explain why or why not.

Respuesta :

Answer:

Yes, the average speed for the entire trip from A to C is equal to [tex]80\frac{km}{h}[/tex]

Step-by-step explanation:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:

[tex]V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}[/tex]

If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:

[tex]V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}[/tex]

We Know that:

[tex]V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}[/tex]

Replacing the values:

[tex]V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}[/tex]

Yes, the average speed for the entire trip from A to C is equal to 80 km/h.

Given

You travel from point A to point B in a car moving at a constant speed of 70 km/h.

You travel the same distance from point B to another point C, moving at a constant speed of 90 km/h.

What is the average speed?

The average speed is defined as the change in displacement and change in a time interval.

The formula is used to calculate average speed;

[tex]\rm Average \ speed= \dfrac{V_1+V_2}{2}[/tex]

Where [tex]\rm V_1[/tex] is 70 and [tex]\rm V_2[/tex] is 90.

Substitute all the values in the formula

[tex]\rm Average \ speed= \dfrac{V_1+V_2}{2}\\\\\rm Average \ speed= \dfrac{70+90}{2}\\\\\rm Average \ speed= \dfrac{160}{2}\\\\\rm Average \ speed= 80[/tex]

Hence, the average speed for the entire trip from A to C is equal to 80 km/h.

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