Respuesta :
Answer:
Yes, the average speed for the entire trip from A to C is equal to [tex]80\frac{km}{h}[/tex]
Step-by-step explanation:
The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:
[tex]V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}[/tex]
If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:
[tex]V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}[/tex]
We Know that:
[tex]V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}[/tex]
Replacing the values:
[tex]V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}[/tex]
Yes, the average speed for the entire trip from A to C is equal to 80 km/h.
Given
You travel from point A to point B in a car moving at a constant speed of 70 km/h.
You travel the same distance from point B to another point C, moving at a constant speed of 90 km/h.
What is the average speed?
The average speed is defined as the change in displacement and change in a time interval.
The formula is used to calculate average speed;
[tex]\rm Average \ speed= \dfrac{V_1+V_2}{2}[/tex]
Where [tex]\rm V_1[/tex] is 70 and [tex]\rm V_2[/tex] is 90.
Substitute all the values in the formula
[tex]\rm Average \ speed= \dfrac{V_1+V_2}{2}\\\\\rm Average \ speed= \dfrac{70+90}{2}\\\\\rm Average \ speed= \dfrac{160}{2}\\\\\rm Average \ speed= 80[/tex]
Hence, the average speed for the entire trip from A to C is equal to 80 km/h.
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