Answer:
The acceleration and time are 588 m/s² and 0.071 sec respectively.
Explanation:
Given that,
Speed = 42.0 m/s
Distance = 1.50 m
(a). We need to calculate the acceleration
Using equation of motion
[tex]v^2=u^2+2as[/tex]
[tex]a=\dfrac{v^2-u^2}{2s}[/tex]
Put the value in the equation
[tex]a=\dfrac{42.0^2-0}{2\times1.50}[/tex]
[tex]a=588\ m/s^2[/tex]
(b). We need to calculate the time
Using equation of motion
[tex]v = u+at[/tex]
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{42.0-0}{588}[/tex]
[tex]t=0.071\ sec[/tex]
Hence, The acceleration and time are 588 m/s² and 0.071 sec respectively.
